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[impossiblewizardry]

fnord888 reblogged your post and added:

Not a contradiction, just a and c can’t be integers (I think can’t be rational, but that’s not a proof of that).

Also, any number that’s not itself perfect square is the same, right?

Yeah, it’s a contradiction under the assumption that a and c are integers.

And yeah, that’s true, it works not just for 2 but any number that is not itself a perfect square.